#!/usr/bin/python
# -*- coding: UTF-8 -*-
if __name__ == '__main__':
n1 = int(raw_input('n1 = :\n'))
n2 = int(raw_input('n2 = :\n'))
n3 = int(raw_input('n3 = :\n'))
def swap(p1,p2):
return p2,p1
___(1)___
print n1,n2,n3
A.if n1 > n2 : n1,n2 = swap(n1,n2)
if n1 > n3 : n1,n3 = swap(n1,n3)
B.if n1 > n2 : n1,n2 = swap(n1,n2)
if n1 > n3 : n1,n3 = swap(n1,n3)
if n2 > n3 : n2,n3 = swap(n2,n3)
C.if n1 > n3 : n1,n3 = swap(n1,n3)
if n2 > n3 : n2,n3 = swap(n2,n3)
D.if n1 > n2 : n1,n2 = swap(n1,n2)
if n2 > n3 : n2,n3 = swap(n2,n3)
【答案】:B
【本题解析】
考察交换排序的算法,比大小后,交换即可